# Extra Questions

from lab11 import *

# Q6
def hailstone(n):
    """
    >>> for num in hailstone(10):
    ...     print(num)
    ...
    10
    5
    16
    8
    4
    2
    1
    """
    "*** YOUR CODE HERE ***"

# Q7
def repeated(t, k):
    """Return the first value in iterable T that appears K times in a row.

    >>> s = [3, 2, 1, 2, 1, 4, 4, 5, 5, 5]
    >>> repeated(trap(s, 7), 2)
    4
    >>> repeated(trap(s, 10), 3)
    5
    >>> print(repeated([4, None, None, None], 3))
    None
    """
    assert k > 1
    "*** YOUR CODE HERE ***"

# Q8
def merge(s0, s1):
    """Yield the elements of strictly increasing iterables s0 and s1, removing
    repeats. Assume that s0 and s1 have no repeats. You can also assume that s0
    and s1 represent infinite sequences.

    >>> m = merge([0, 2, 4, 6, 8, 10, 12, 14], [0, 3, 6, 9, 12, 15])
    >>> type(m)
    <class 'generator'>
    >>> list(m)
    [0, 2, 3, 4, 6, 8, 9, 10, 12, 14, 15]
    >>> def big(n):
    ...    k = 0
    ...    while True: yield k; k += n
    >>> m = merge(big(2), big(3))
    >>> [next(m) for _ in range(11)]
    [0, 2, 3, 4, 6, 8, 9, 10, 12, 14, 15]
    """
    i0, i1 = iter(s0), iter(s1)
    e0, e1 = next(i0, None), next(i1, None)
    "*** YOUR CODE HERE ***"

# Q9
def remainders_generator(m):
    """
    Takes in an integer m, and yields m different remainder groups
    of m.

    >>> remainders_mod_four = remainders_generator(4)
    >>> for rem_group in remainders_mod_four:
    ...     for _ in range(3):
    ...         print(next(rem_group))
    0
    4
    8
    1
    5
    9
    2
    6
    10
    3
    7
    11
    """
    "*** YOUR CODE HERE ***"

# Q10
def zip_generator(*iterables):
    """
    Takes in any number of iterables and zips them together.
    Returns a generator that outputs a series of lists, each
    containing the nth items of each iterable.
    >>> z = zip_generator([1, 2, 3], [4, 5, 6], [7, 8])
    >>> for i in z:
    ...     print(i)
    ...
    [1, 4, 7]
    [2, 5, 8]
    """
    "*** YOUR CODE HERE ***"