.data
	# This shows you can use a .word and directly encode the value in hex
	# if you so choose
num1:	.word 0x3F800000#CHANGE ME
num2:	.float 1.0
num3:	.word 0x00000000#CHANGE ME
result1:.word 0
result2:.word 0#use this if you wish
string: .asciiz "\n"

	.text
main:
	la $t0, num1#load address of first floating number
	lwc1 $f2, 0($t0)#load num1 into a fp register
	lwc1 $f4, 4($t0)
	lwc1 $f6, 8($t0)
	lw $s0 0($t0)#load num1 into a regular register
	# Print out the values of the summands

	#num1
	li $v0, 2
	mov.s $f12, $f2
	syscall	
	jal printNewline
	
	#num1 hex
	li $v0, 34
	move $a0 $s0
	syscall
	jal printNewline
	
	#num2 (1.0)
	li $v0, 2
	mov.s $f12, $f4
	syscall
	jal printNewline
	jal printNewline

	# Do the actual addition

	add.s $f12, $f2, $f4

	# Transfer the value from the floating point reg to the integer reg

	swc1 $f12, 12($t0)
	lw $s0, 12($t0)

	# At this point, $f12 holds the sum, and $s0 holds the sum which can
	# be read in hexadecimal

	#sum
	li $v0, 2
	syscall
	jal printNewline
	
	#sum hex
	li $v0, 34
	move $a0 $s0
	syscall
	jal printNewline
	jal printNewline
	
	#PART 2
	#add num1, num2, num3 in 2 different orders to get 2 different results. 
	#Print out the hex values of the two sums.
	
	#exit
	li $v0, 10
	syscall
	
printNewline:
	li $v0, 4
	la $a0, string
	syscall
	jr $ra