Second-order cone
Definition
The set in \(\mathbf{R}^{n+1}\)
\[
\mathbf{K}_{n} :=\left\{ (x,y) \in \mathbf{R}^{n+1} : y \ge \|x\|_2 \right\}
\]
is a convex cone, called the second-order cone.
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Example: The second-order cone is sometimes called ‘‘ice-cream cone’’. In \(\mathbf{R}^3\), it is the set of triples \((x_1,x_2,y)\) with
\[
y^2 \ge x_1^2+x_2^2, \;\; y \ge 0.
\]
The blue circle corresponds to the set
\[
\left\{ (x_1,x_2,y) : y = 1 \ge \sqrt{x_1^2+x_2^2}
\right\}.
\]
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Proof of convexity
The fact that \(\mathbf{K}_{n}\) is convex can be proven directly from the basic definition of a convex set. Alternatively, we may express \(\mathbf{K}_{n}\) as an intersection of half-spaces, as follows.
From the Cauchy-Schwartz inequality, we have
\[
y \ge \|x\|_2 \Longleftrightarrow \forall \: u, \;\; \|u\|_2 \le 1 : y \ge u^Tx ,
\]
we have
\[
\mathbf{K}_{n} = \bigcap_{u \::\: \|u\|_2 \le 1} \left\{ (x,y) \in \mathbf{R}^{n+1} : y \ge u^Tx \right\} .
\]
Each one of the sets involved in the intersection is a half-space.
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